20x^2+62xy-28y^2=

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Solution for 20x^2+62xy-28y^2= equation:


Simplifying
20x2 + 62xy + -28y2 = 0

Reorder the terms:
62xy + 20x2 + -28y2 = 0

Solving
62xy + 20x2 + -28y2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2'.
2(31xy + 10x2 + -14y2) = 0

Factor a trinomial.
2((5x + -2y)(2x + 7y)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(5x + -2y)' equal to zero and attempt to solve: Simplifying 5x + -2y = 0 Solving 5x + -2y = 0 Move all terms containing x to the left, all other terms to the right. Add '2y' to each side of the equation. 5x + -2y + 2y = 0 + 2y Combine like terms: -2y + 2y = 0 5x + 0 = 0 + 2y 5x = 0 + 2y Remove the zero: 5x = 2y Divide each side by '5'. x = 0.4y Simplifying x = 0.4y

Subproblem 2

Set the factor '(2x + 7y)' equal to zero and attempt to solve: Simplifying 2x + 7y = 0 Solving 2x + 7y = 0 Move all terms containing x to the left, all other terms to the right. Add '-7y' to each side of the equation. 2x + 7y + -7y = 0 + -7y Combine like terms: 7y + -7y = 0 2x + 0 = 0 + -7y 2x = 0 + -7y Remove the zero: 2x = -7y Divide each side by '2'. x = -3.5y Simplifying x = -3.5y

Solution

x = {0.4y, -3.5y}

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